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x^2+x/5-1/5=0
We multiply all the terms by the denominator
x^2*5+x-1=0
Wy multiply elements
5x^2+x-1=0
a = 5; b = 1; c = -1;
Δ = b2-4ac
Δ = 12-4·5·(-1)
Δ = 21
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{21}}{2*5}=\frac{-1-\sqrt{21}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{21}}{2*5}=\frac{-1+\sqrt{21}}{10} $
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